1840 United States presidential election in New Hampshire
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 County Results
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| Elections in New Hampshire |
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A presidential election was held in New Hampshire on November 2, 1840 as part of the 1840 United States presidential election.[1] Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.
Results
[edit]| 1840 United States presidential election in New Hampshire[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 32,774 | 54.66% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 26,310 | 43.88% | 0 | 0.00% | ||
| Liberty | James G. Birney of New York | Thomas Earle of Pennsylvania | 872 | 1.45% | 0 | 0.00% | ||
| Total | 59,956 | 100.00% | 7 | 100.00% | ||||
See also
[edit]References
[edit]- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
- ^ "1840 Presidential General Election Results – New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.
State and district results of the 1840 United States presidential election | ||
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