1918 Connecticut Attorney General election
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  Healy: 50–60% 60–70% 70–80% 80–90% Hewitt: 50–60% 60–70% 70–80% Tie: 50% | |||||||||||||||||
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The 1918 Connecticut Attorney General election was held on 5 November 1918 in order to elect the Attorney General of Connecticut. Republican nominee and incumbent member of the Connecticut House of Representatives Frank E. Healy defeated Democratic nominee Harrison Hewitt.[1]
General election
[edit]On election day, 5 November 1918, Republican nominee Frank E. Healy won the election by a margin of 6,949 votes against his opponent Democratic nominee Harrison Hewitt, thereby retaining Republican control over the office of Attorney General. Healy was sworn in as the 6th Attorney General of Connecticut in 1919.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Frank E. Healy | 83,953 | 52.16% | |
| Democratic | Harrison Hewitt | 77,004 | 47.84% | |
| Total votes | 160,957 | 100.00% | ||
| Republican hold | ||||
References
[edit]- ^ "Harrison Hewitt (D)". electionhistory.ct.gov. Retrieved October 20, 2024.
- ^ "1918 Nov 5 :: General Election :: Attorney General :: State of Connecticut". electionhistory.ct.gov. Retrieved October 20, 2024.