File:Go-Ahead London LT274 (LTZ1274) Old Kent Road 11.11.2023.jpg
_Old_Kent_Road_11.11.2023.jpg){kind=small}
Size of this preview: 800 × 531 pixels. Other resolutions: 320 × 213 pixels | 640 × 425 pixels | 1,024 × 680 pixels | 1,280 × 850 pixels | 2,048 × 1,360 pixels.
Original file (2,048 × 1,360 pixels, file size: 816 KB, MIME type: image/jpeg)
 | This is a file from the Wikimedia Commons. Information from its description page there is shown below. Commons is a freely licensed media file repository. You can help. |
Summary
| Description |
English: TfL route 21 |
| Date | |
| Source | https://www.flickr.com/photos/martinruthe/53329164180/ |
| Author | Martin Ruthe's Transport Photos |
Licensing
This file is licensed under the Creative Commons Attribution-Share Alike 2.0 Generic license.
- You are free:
- to share – to copy, distribute and transmit the work
- to remix – to adapt the work
- Under the following conditions:
- attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
- share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original.
|
This image was originally posted to Flickr by Martin Ruthe's Transport Photos at https://flickr.com/photos/162585271@N04/53329164180. It was reviewed on 19 February 2024 by FlickreviewR 2 and was confirmed to be licensed under the terms of the cc-by-sa-2.0. |
File history
Click on a date/time to view the file as it appeared at that time.
| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 13:53, 19 February 2024 | | 2,048 × 1,360 (816 KB) | Pedroperezhumberto | Uploaded a work by Martin Ruthe's Transport Photos from https://www.flickr.com/photos/martinruthe/53329164180/ with UploadWizard |
File usage
The following page uses this file:
_Old_Kent_Road_11.11.2023.jpg){kind=link}